Question

What is the value of x for the following equation: 26|2x+1|=52?

Accepted Answer

We have to find x given that 26|2x+1|=52.
26|2x+1|=52
cancel 26 from both the sides.
=> |2x + 1| = 2
Now |x| represents the absolute value of x and has the same value for x as well as -x.
=> 2x + 1 = 2 and 2x + 1 = -2
=> 2x = 1 and 2x = -3
=> x = 1/2 and x = -3/2
Therefore we get x is equal to 1/2 and -3/2

Answer

To find x if 26|2x+1| = 52.
Solution:
26|2x+1| = 52.
We divide both sides by 26:
|2x+1| = 2.
|2x+1|=2 implies 2x+1 = 2, or 2x+1 = -2 = 2.
If 2x+1 = 2, then 2x= 2 -1 = 1, so 2x/-2 = 1/2 . So x= -1/2.
If 2x+1 = -2, then 2x = -2-1 = -3. So 2x/2 = -3/2 = -3/2 = -3/2
Therefore if 26|2x+1| = 52, then x= 1/2 or x= -3/2.

Answer

For the beginning, we'll discuss the modulus. Case 1: l 2x + 1 l = 2x + 1 for 2x + 1 >= 0 2x >= -1 x >= -1/2 Now, we'll solve the equation: 26(2x + 1) = 52 We'll divide by 26: 2x + 1 = 2 We'll subtract 1 both sides, to isolate x to the left side: 2x = 2-1 We'll divide by 2: x = 1/2 Since x =1/2 is in the interval of admissible values,[-1/2, +infinite], we'll accept it. Case 2: l 2x + 1l = -2x - 1 for 2x + 1 < 0 2x < -1 x < -1/2 Now, we'll solve the equation: 26(-2x - 1) = 52 -2x - 1 = 2 We'll add 1 both sides: -2x = 3 x = -3/2 Since x = -3/2 belongs to the interval of admissible values, (-infinite, -1/2), we'll accept it, too. The solutions of the given equation are: {-3/2 ; 1/2}.

Math

What is the value of x for the following equation: 26|2x+1|=52?

Expert Answers

We’ll help your grades soar

Related Questions

solve the equation: 2^(2x-1)= 8^x

Solve the following modulus equation: |x-1| = |x| +1

Solve the following quadrtatic equation. 5x²+2x+1=0

2cosx + 1 = 0 find x values for the interval [0, 2pi]

Solve the following exponential equation: `3^(2x+1)=243` .