# what is the value of p(x)=xsquare-3x-4 at x=2

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### 1 Answer

Supposing that you need to find the value of `p(x) = x^2 - 3x - 4` at x=2, you need to substitute 2 for x in equation `p(x) = x^2 - 3x - 4` such that:

`p(2) = 2^2 - 3*2 - 4`

`p(2) = 4 - 6 - 4`

Reducing like terms yields:

`p(2) = -6`

**Hence, evaluating the value of `p(x) = x^2 - 3x - 4` at x=2 yields `p(2) = -6` .**