We have to determine if i^231 is real or complex.

Now i^2 = -1 , i^4 = 1

i^231 = i^228 * i^3

=> i^228* i^2*i

=> 1*-1*i

=> -i

**Therefore i^231 is complex and equal to -i.**

Posted on

Given the number i^231

Let us simplify and determine the values.

First we will rewrite the power.

==> i^(231) = i^(3+228)

Now we will use exponent properties to simplify.

We know that x^(a+b) = x^a * x^b

==> i^(3+228) = i^3 * i^228

But we know that i^2 = -1 ==> i^3 = -1*i = -i

==> i^231 = -i * (i^228)

Now we will rewrite the power again.

==> i^231 = -i * i^(2*114)

From exponent properties we know that x^ab = x^a^b

==> i^231 = -i *( i^2)^114

But i^2 = -1

==> i^231 = -i * (-1)^114

==> i^231 = -i * 1 = -i

**==> i^231 = -i, and it is a complex number (-sqrt-1)**

Posted on

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now