What is the value of Kp for this reaction: 2SO2(g)+O2(g)<->2SO3(g)?

Asked on by ksho94

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gsenviro | College Teacher | (Level 1) Educator Emeritus

Posted on

The equilibrium constant for a given reaction

aA + bB -><- cC + dD is given as

Kp = (C)^c x (D)^d  / ((A)^a  x (B)^b)

where (C) is the partial pressure for gas C.

In the given case, Kp = (SO3)^2 / ((SO2)^2 x (O2)) 

You will need to substitute the values of partial pressure for each of these gases to get the answer.

Good luck.


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