For what value of k do the four points (1, 1, -1), (0, 3, -2), (-2, 1, 0), and (k, 0, 2) all lie in a plane?

Expert Answers

An illustration of the letter 'A' in a speech bubbles

You should consider the condition for the 4 points to be coplanar,hence, you need to evaluate the volume of tetrahedron defined by the points and then you need to solve the equation V=0, such that:

`V = [(1, 1, -1, 1),(0, 3, -2, 1), (-2, 1, 0, 1), (k, 0, 2, 1)]` 

`V = (-1)^(1+1)*1*[(3,-2,1),(1,0,1),(0,2,1)] + (-1)^(3+1)*(-2)*[(1,-1,1),(3,-2,1),(0,2,1)] + (-1)^(4+1)*k*[(1,-1,1),(3,-2,1),(1,0,1)]`

`V = (2-6+2) - 2(-2+6-2+3) - k(-2-1+2+3)`

`V = -2 - 10 - 2k`

Hence, all four points are coplanar if the volume of tetrahedron is zero such that:

`-2 - 10 - 2k = 0 => -12- 2k = 0 => -2k = 12 => k = -6`

Hence, evaluating the value of k for the given points to be coplanar yields `k = -6` .

See eNotes Ad-Free

Start your 48-hour free trial to get access to more than 30,000 additional guides and more than 350,000 Homework Help questions answered by our experts.

Get 48 Hours Free Access
Approved by eNotes Editorial Team