What are the two consecutive odd numbers such that three times the first is 5 more than twice the second.

Expert Answers

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If we take the two odd numbers a A and B. we have that B = A + 2.

As three times the first is 5 more than twice the second.

=> 3*A = 5 + 2*B

=> 3A = 5 + 2( A + 2)

=> 3A = 5 + 2A + 4

=> 3A = 9 + 2A

=> A = 9

B = A + 2 = 9 +2 = 11

Therefore the numbers are 9 and 11.

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Let the first number be x.

Then the next odd number will be x+2.

Now given that 3 times the first = 5 more that twice the second.

We will translate into algebraic equation.

==> 3*(x) = 5 + 2(x+2)

==> 3x = 5 + 2x + 4

==> 3x = 2x + 9

We will subtract 2x from both sides.

==> x = 9

Then the first number is 9, and the next odd number will be 9+2=11

Then, the numbers are 9 and 11.

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