# What is the surface area of cylinder with radius of 2 cm and height 8 cm?

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### 7 Answers

We know that the surface area of the cylinder is:

Surface area = area of the bases + area of the sides

The area of the bases = 2* area of the circle

= 2* r^2 *pi

The area of the side = circumference of the circle * height of the cylinder

= 2*pi*r * h

Then the surface area is:

Surface area = 2r^2 * pi + h* 2*pi*r

Given r = 2 and h = 8

==> surface area = 2*(2^2)*pi + 8*2*pi*2

= 8pi + 32pi

= 40pi

= 125.66

**Then the surface area is : 125.66 cm^2**

### User Comments

What we know:

- SA= `2pir^(2)+2pirh`
- r=2cm
- h=8cm
- `pi=3.14`

Plug in what we know into the surface area formula for cylinders

- SA=`2pi(2)^(2)+2pi(2)(8)`

Simplify

- SA=`125.6 cm^(2)`

Surface area of a cylinder:

the formula is (2*pi*r^2) + (2*pi*r*h)

*r=2 cm *

*h=8 cm*

*(2*3.14*2^2)+(2*3.14*2*8)*

*25.12 + 100.48*

*125.6 cm^2*

Surface Area= 2*pie*r*h+2*pie*r^2

r=2cm h=8cm

(2*3.14*2*8)+(2*3.14*2^2)

125.6cm2

The formula for the surface area of a cylinder is : (2 X pi X r2) plus ( 2 X radius X height).

So you would do ( 2 X 3.14 X 2 ( to the second power) plus ( 2 X 3.14 X 2 X 8)

Then you would multiply then add all those numbers up and the answer should be 125.6 cm2

125.66 sqcm

The curved surface are of a cylinder is given by: A1 = 2pirh where r = is radius and h is height.

The area of the top surface A2 = pir^2.

The bottom surface area A2 = pir^2.

Therefore the total surface area of the cylinder = A1+A2+A3 = 2pirh+2pir^2 = 2pir (h+r).

Give the radius = 2cm and h = 8cm.

Therefore the curved surface area A1 = 100.5310 sq cm

Therea of top and bottom surface area = A2=A3 = 12.5664 sq cm.

Therefore the total surface area of the cylinder = 100.5310+2*12*5664 = 113.0974 = 125.66 sq cm nearly.