What is the surface area of cylinder with radius of 2 cm and height 8 cm?
We know that the surface area of the cylinder is:
Surface area = area of the bases + area of the sides
The area of the bases = 2* area of the circle
= 2* r^2 *pi
The area of the side = circumference of the circle * height of the cylinder
= 2*pi*r * h
Then the surface area is:
Surface area = 2r^2 * pi + h* 2*pi*r
Given r = 2 and h = 8
==> surface area = 2*(2^2)*pi + 8*2*pi*2
= 8pi + 32pi
Then the surface area is : 125.66 cm^2
What we know:
- SA= `2pir^(2)+2pirh`
Plug in what we know into the surface area formula for cylinders
- SA=`125.6 cm^(2)`
Surface Area= 2*pie*r*h+2*pie*r^2
Surface area of a cylinder:
the formula is (2*pi*r^2) + (2*pi*r*h)
25.12 + 100.48
The formula for the surface area of a cylinder is : (2 X pi X r2) plus ( 2 X radius X height).
So you would do ( 2 X 3.14 X 2 ( to the second power) plus ( 2 X 3.14 X 2 X 8)
Then you would multiply then add all those numbers up and the answer should be 125.6 cm2
The curved surface are of a cylinder is given by: A1 = 2pirh where r = is radius and h is height.
The area of the top surface A2 = pir^2.
The bottom surface area A2 = pir^2.
Therefore the total surface area of the cylinder = A1+A2+A3 = 2pirh+2pir^2 = 2pir (h+r).
Give the radius = 2cm and h = 8cm.
Therefore the curved surface area A1 = 100.5310 sq cm
Therea of top and bottom surface area = A2=A3 = 12.5664 sq cm.
Therefore the total surface area of the cylinder = 100.5310+2*12*5664 = 113.0974 = 125.66 sq cm nearly.