What is the surface area of the cylinder whose radius is 6 in and the height is 17 in.

Expert Answers

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Given the cylinder such that the radius of the base is (r) = 6 in

Also, given that the height of the cylinder is (h) = 17 in.

We need to find the surface area of the cylinder.

We know that the surface area of the cylinder is given by the following equation.

SA = 2*area of the base + area of the side.

==> SA = 2*A1 + A2

Let us calculate the area of the base.

We know that the area of the circle = r^2*pi

==> A1 = 36*pi = 113.1 in^2

Now we need to find the area of the sides.

A2 = circumference of the base * h

       = 2*pi*r * h

         = 2*6*pi*17 = 204*pi = 640.9 in^2

Now we will substitute into the surface area.

SA = 2*A1 + A2

     = 2*113.1 + 640.9

      = 226.2 + 640.9 = 867.1 in^2 (approx.)

Then, the surface area of the cylinder is 867.1 in^2

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