# What is the sum of: 3/4(8p+12)+ 3/8(16p-8)

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### 5 Answers

To solve for `3/4(8p+12)+ 3/8(16p-8)`

Multiply all the factors in `3/4(8p+12)+ 3/8(16p-8)` .

`(3(8p+12))/4 + (3(16p-8))/8`

Factor out the GCF of `4` from `8p+12` .

`(3(4(2p+3)))/4 + (3(16p-8))/8`

Multiply 3 by `4` to get `12` .

`((12)(2p+3))/4 + (3(16p-8))/8`

Reduce the expression by canceling out all common factors from the numerator and denominator.

`3(2p+3)+(3(16p-8))/8`

Multiply `3` by each term inside the parentheses.

`6p + 9 + (3(16p-8))/8`

Factor out the GCF of `8` from `16p-8` .

`6p + 9 + (3(8(2p-1)))/8`

Multiply `3` by `8` to get `24` .

`6p + 9 + ((24)(2p-1))/8`

Reduce the expression by canceling out all common factors from the numerator and denominator.

`6p+9+3(2p-1) `

Multiply `3` by each term inside the parentheses.

`6p+9+6p-3`

Combine all similar terms in the polynomial `6p+9+6p-3` .

Therefore, the answer is `12p+6`

Find the sum of `3/4(8p + 12) + 3/8(16p-8).`

First, distribute the fractions.

`3/4(8p) + 3/4(12) + 3/8(16p) - 3/8(8)`

`6p + 9 + 6p - 3`

Combine like terms.

`12p + 6`

**The sum is `12p + 6` .**

3/4 ( 8p + 12 ) + 3/8 ( 16p - 8 )

First distribute the 3/4 and the 3/8. By distributing, you should get

6p + 9 + 6p - 3 now combine the like terms ( 6p with 6p and 9 with -3 )

By combining like terms, you should get

12p + 6 since you can not simplify this answer anymore this is your answer

`3 / 4 ( 8 p + 1 2 )+ 3 / 8 ( 1 6 p - 8) `

`3 / 4 `

`3 / 8 `

multiply each number in the parentheses by the number on the outside of it:

`3/4 xx 8p = 6p `

`3/4 xx 12 = 9 `

`6 p + 9 + 3/8 (1 6 p - 8) `

`3/8 xx 16p = 6p `

`3/8 xx -8 = -3 `

`6p + 9 + 6p - 3 `

combine like terms

`12p + 6`

`3/4(8p+12)+ 3/8(16p-8)`

`=3/4*8*p+3/4*12+3/8*16*p-3/8*8`

`=3*2*p+3*3+3*2*p-3*1`

`=6p+6p+9-3`

`=12p+6`

`=6(2p+1)`