What are solutions of simultaneous equations 1/x=(y-1)/y 3/x=(2y-1)/y

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We have to solve the equations 1/x=(y-1)/y and 3/x=(2y-1)/y

1/x=(y-1)/y

=> x = y/(y - 1)

Substitute x = y/ (y - 1) in 3/x=(2y-1)/y

=> 3/x=(2y-1)/y

=> 3 /[y/ (y - 1)] = (2y-1)/y

=> 3(y - 1)/y = (2y - 1)/y

=> 3y - 3 = 2y -...

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We have to solve the equations 1/x=(y-1)/y and 3/x=(2y-1)/y

1/x=(y-1)/y

=> x = y/(y - 1)

Substitute x = y/ (y - 1) in 3/x=(2y-1)/y

=> 3/x=(2y-1)/y

=> 3 /[y/ (y - 1)] = (2y-1)/y

=> 3(y - 1)/y = (2y - 1)/y

=> 3y - 3 = 2y - 1

=> y = 2

x = 2/(2 - 1) = 2

Therefore we get x = 2 and y = 2

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