What is the solution for x: 3x + 19y = 6, 4x + 21y = 4

Expert Answers

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We have to solve the following equations for x:

3x + 19y = 6 ...(1)

4x + 21y = 4 ...(2)

As we only have to find x, we can substitute for y in (1) using (2)

From (2) we get

21y = 4 - 4x

=> y = (4 - 4x)/21

Substitute in (1)

3x + 19(4 - 4x)/21 = 6

=> 63x + 76 - 76x = 126

=> -13x = 50

=> x = -50/13

The required value of x = -50/13

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