The solution of the equation x^3+3x^2+4x+12=0 has to be determined.

x^3+3x^2+4x+12=0

=> x^2(x + 3) + 4(x + 3) = 0

=> (x^2 + 4)(x + 3) = 0

x^2 + 4 = 0

=> x = 2i and x = -2i

x + 3 = 0

=> x = -3

**The solution set of x^3+3x^2+4x+12=0 is {-2i, 2i, -3}**

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