`(2x+3)/x >=x` apply miltiplication property
`2x+3>=x^2` apply subtraction property
`x^2-2x-3<=0` factor the polynomial
`(x-3)(x+1)<=0` so x must be `<=` 3 and x must also be `>= -1`
remembering that we can not divide by zero, we get the solution set must be all values of `-1 <= x <=3, but != 0`
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