l 4x-3 l -1 > 12
First we will add 1 to both sides.
==> l 4x-3 l > 13
Now by definition we will rewrite:
==> 4x-3 > 13 OR 4x-3 < -13
We will solve both cases:
==> 4x-3 > 13
==> 4x > 16
==> x > 4 ............(1)
==> 4x-3 < -13
==> 4x < -10
==> x < -10/4
==> x < -5/2 ............(2)
Then the solution is :
x belongs to ( -inf, -5/2) U (4, inf)
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