# What is the solution for in and out table, 1 in 2 out, 2 in 4 out, 3 in 7 out, 4 in ? out, 5 in and ? out.

Asked on by lukenac

rakesh05 | High School Teacher | (Level 1) Assistant Educator

Posted on

In          1          2       3          4         5

out         2         4       7           --       --

From the above pattern we observe that every successive out term is a sum of  previous out+current In.

i.e.       the secon out 4= first out 2+second In 2

the third out 7= second out 4+third in 3

the fourth out =third out 7+ fourth In 4

=11

the fifth out= fourth out 11+ fifth In 5

=16.

So,      the numbers are    11 and 16.

kmieciakp | High School Teacher | (Level 2) Assistant Educator

Posted on

11 and 16-- add the in to the out before it--

1+1=2; 2+2=4; 3+4=7; 4+7=11; 5+11=16

atyourservice | Student, Grade 11 | (Level 3) Valedictorian

Posted on

1    2    3     4     5

2    4    7    11    16

The reason I got those numbers is because it seems like the in is being added to the previous out:

like:

2+2=4

4+3=7

7+4=11

11+5=16

ricrobrod | Elementary School Teacher | (Level 1) eNoter

Posted on

in   1   2   3    4    5

out   2   4   7   11  16

If you add the 'out' number to the following 'in' number, you will get the next 'out' number. So, 2+2=4, 4+3=7, 7+4=11, 11+5=16. Your solution is 11 and 16.

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