What is the solution of 3x^2 + 14x + 15 = 0

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justaguide | College Teacher | (Level 2) Distinguished Educator

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The solution of the equation: 3x^2 + 14x + 15 = 0 has to be determined.

The roots of any quadratic equation ax^2 + bx + c = 0 are `x1 = (-b +sqrt(b^2 - 4ac))/2a` and `x1 = (-b -sqrt(b^2 - 4ac))/2a`

For the given quadratic equation:

x1 = `(-14 + sqrt(16))/6` = `-14/6 + 4/6` = `-10/6` = `-5/3`

x2 = `(-14 - sqrt(16))/6` =` -14/6 - 4/6` = `-18/6` = `-3`

The solutions of 3x^2 + 14x + 15 = 0 are x = `-5/3` and x = `-3`

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