We have to find the solution for 3(2m − 1) <= 4m + 7
3(2m − 1) <= 4m + 7
=> 6m − 3 <= 4m + 7
=> 6m - 4m <= 7 + 3
=> 2m <= 10
=> m <= 5
The solution for the given inequality lies in the interval (-inf., 5]
We have to find the solution for 3(2m − 1) <= 4m + 7
3(2m − 1) <= 4m + 7
=> 6m − 3 <= 4m + 7
=> 6m - 4m <= 7 + 3
=> 2m <= 10
=> m <= 5
The solution for the given inequality lies in the interval (-inf., 5]