We have to find the smallest value of x for which y = sin(3x + pi/2) has the maximum value.

The sine function can have a maximum value of 1.

We know that y = sin (3x + pi/2) = 1. The least value of x for which the sine...

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We have to find the smallest value of x for which y = sin(3x + pi/2) has the maximum value.

The sine function can have a maximum value of 1.

We know that y = sin (3x + pi/2) = 1. The least value of x for which the sine function has a value of 1 is pi/2.

This gives 3x + pi/2 = pi/2

=> 3x = 0

=> x = 0

**The function y = sin(3x + pi/2) has the maximum value when x = 0**