1 Answer | Add Yours
The slope of a line tangent to the curve y = f(x) at the point where x = a is given by the value of f'(a).
For the curve defined by y = 4x^3 - 3x^2 + 10, the derivative `dy/dx` = 4*3*x^2 - 3*2*x = 12x^2 - 6x.
At the point where x = 1, `dy/dx` = 12 - 6 = 6
The slope of the tangent to the curve y = 4x^3 - 3x^2 + 10 at the point (1, 11) is 6.
We’ve answered 318,922 questions. We can answer yours, too.Ask a question