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We have the equation of the line as : 4x+2y=12
=> 2y = 12 - 4x
=> y = 6 - 2x
A line with a slope m and y-intercept c can be written as y = mx + c
In the case of y = -2x - 6, the slope is -2.
The required slope is -2.
The slope of the line ax+by+c = 0 is gotten by writing the equation in the slope intercept form y = mx+c, where m is the slope and c is the y intercept.
ax+by+c = 0.
=> by = -ax-c.
y = (-a/b) +(-c/a), where (-a/b) is the slope of the line ax+by+c = 0.
So 4x+2y = 12 could be written as:
2y = -4z+12.
=> 2y/2 = (-4x/2)+12/2.
=> y = -2x+6 which is in slope intercept form like y = mx+c. So slope m = -2.
So the slope of the line 4x+2y= 12 is -2.
First, we need to put the equation in the point slope form:
Y = mx + n, where m represents the slope.
For this reason, we'll have to subtract 4x both sides:
4x - 4x + 2y = 12 - 4x
We'll eliminate like terms:
2y = -4x + 12
We'll divide by 2:
y = -4x/2 + 12/2
We'll simplify and we'll get:
y = -2x + 6
The slope is m = -2.
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