We have the function f(x) =2x^3 + e^2x + sin 2x - ln x. We have to find f''(x).

f'(x) = 6x^2 + 2e^2x + 2 cos 2x - 1/x

f''(x) = 12x + 4e^2x - 4 sin 2x + 1/x^2

**The required second derivative f(x) = 12x + 4e^2x - 4 sin 2x + 1/x^2**

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