What are the roots of the equation 5x^2 + 8x - 4 = 0. Do not use quadratic formula

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rakesh05 | High School Teacher | (Level 1) Assistant Educator

Posted on

Given equation is `5x^2+8x-4=0` . {To factorise `ax^2+bx+c`

we use the criteria that we multiply a and c and then break this number into two parts in such a way that sum of the parts is equal to the coefficient of `x.`

Now this equation we can write as

         `5x^2+(10-2)x-4=0`

or,      `5x^2+10x-2x-4=0`

or,      `(5x^2+10x)-(2x+4)=0`

or,       `5x(x+2)-2(x+2)=0`

or,        `(5x-2)(x+2)=0`

or,         `5x-2=0`     and  `(x+2)=0`

or,         `5x=2`          and        `x=-2`

or,          `x=2/5`         and        `x=-2`

So the roots of the given quadratic equation are `2/5 and -2.`

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justaguide | College Teacher | (Level 2) Distinguished Educator

Posted on

The roots of the equation 5x^2 + 8x - 4 = 0 have to be determined.

5x^2 + 8x - 4 = 0

=> 5x^2 + 10x -2x - 4 = 0

=> 5x(x + 2) - 2(x + 2) = 0

=> (5x - 2)(x + 2) = 0

5x - 2

=> x = 2/5

x + 2 = 0

=> x = -2

The roots of the equation 5x^2 + 8x - 4 = 0 are {-2, 2/5}

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