# what are the roots of the equation: 2x^2-5x+1=0

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### 2 Answers

Given the quadratic equation:

2x^2 - 5x + 1 = 0

We will use the quadratic formula to find the roots.

==> x = [ -b +- sqrt(b^2 - 4ac)]/2a

==> a = 2 b= -5 c = 1

==> x1= [ 5 + sqrt(25-8)]/ 4 = [ 5+ sqrt17]/4

==> x2= (5-sqrt17)/4

Then the roots are:

**x = { (5+sqrt17)/4 , (5-sqrt17)/4 }**

2x^2-5x +1 = 0

To find the roots:

2x^2-5x^2 = 1

Divide by 2.

x^2 - 2.5x= -0.5.

x^2-2.5x+(2.5/2)^2 = -0.5+(2.5/2)^2.

(x- 1.25)^2 = +or-sqrt1.0675

x = 1.25 +or- sqrt 1.0675

**x = (5+or-sqrt17)/4**.