What are the real solutions of the equation? log2(x+1)+log2(x-2)=2

Expert Answers info

justaguide eNotes educator | Certified Educator

calendarEducator since 2010

write12,544 answers

starTop subjects are Math, Science, and Business

We have to find the solution of log(2)(x+1) + log(2)(x-2) = 2

log(2)(x+1) + log(2)(x-2) = 2

use log a + log b = log a*b

=> log(2)...

(The entire section contains 82 words.)

Unlock This Answer Now


check Approved by eNotes Editorial


giorgiana1976 | Student

Since the bases of the logarithms are matching, we'll apply the product property:

log 2(x+1)+log2(x-2)=log2 [(x+1)(x-2)]

We'll re-write the equation:

log2 [(x+1)(x-2)] = 2

We'll take antilogarithms:

[(x+1)(x-2)] = 2^2

[(x+1)(x-2)] = 4

We'll remove the brakets:

x^2 - x - 2 - 4 = 0

x^2 - x - 6 = 0

We'll apply quadratic formula:

x1 = [1+sqrt(1 + 24)]/2

x1 = (1 + 5)/2

x1 = 3

x2 = -2

Since the common interval of admissible values for x (values that make the logarithms to exist) is (2 , +infinite), we'll reject the negative value and we'll keep as solution of equation only x = 3.

check Approved by eNotes Editorial