# What is the product of the slopes of perpendicular lines and why is this product always negative?

*print*Print*list*Cite

Expert Answers

Student Comments

neela | Student

Let the equation of the two lines be:

y=m1*x+c1 and

y=m2*x+c2, where m1 and m2 are the slopes of the lines and c1 and c2 are their intercepts on the Y axis.

The angles A and B by the above two the lines with X axis is given by:

tanA = m1 and tan B = m2.

Therefore, the angle between the two lines, B-A is given by:

Tan(A-B) = (tanA-tanB)/{1+tanA*tanB}.............(1)

When A-B is a right angle or 90 degrees, Tan(A-B) is tan 90 degrees , which should be infinite. Or the denominator on the right side of equation at (1) is zero or 1+tanA*tan B =0 or tanA*tan B=-1 or m1*m2=-1 or the product of the slope must be equal to minus one.

So,the product of the slopes of the lines is mimus one, when they are at right angles or perpendicular to each other.