What is the probability the spinner stops on:1) 32) number less than 43) even numberThe sample space for the spinner is (1,2,3,4,5,6)Please help me find the probability for each question.
There are six possibilities for where the spinner will stop. To figure out any particular chance, count how many times out of 6 it could happen.
1) Any one number -- such as 3 -- has a probability of 1 in 6 or 1/6.
2) There are three numbers less than four, so the probability of landing on one of them is 3 in 6, or 1/2.
3) The same is true of landing on an even number. There are three possible stopping places that are even, so the probability is 3 in 6 or 1/2 again.
1.) There is only one number 3 on your spinner out of 6 total. This will make your probability 1/6.
2.) There are 3 numbers less than 4 on the spinner out of 6 total numbers. This gives you the probability of 3/6 or 1/2.
3.) There are 3 even numbers out of 6, which makes the probability 3/6 or 1/2.
1) There is one 3 in the range, and there is six numbers in the sample space, so P= 1/6
2) There is 3 numbers less than 4 which is 1,2 and 3, so P= 3/6=1/2
3)There is three even numbers 2,4 and 6 so P= 3/6 = 1/2
1) you have six numbers and one of them is three so you would have 1/6 of a chance to get three
2) infering that number doesn't include 4 you would have 1/2 (3/6) of a chance
3) to get a even number (2,4,6) you would have 1/2 (3/6) of a chance
I think it is 3 bacause the spinner could land on even numbers
or it can land on all the numbers