what is the pH of a .0020M NaOH solution?
You need to evaluate pH using the following equation, such that:
`pH = -log(NaOH)`
Since the problem provides the concentration of `0.002M` , you need to replace it in formula above:
`pH = -log(0.002) => pH = -(-2.69) => pH = 2.69`
Hence, evaluating the pH of the `.002 M NaOH` solution yields `pH = 2.69.`