What is the period of `sin^2x - cos^2x`

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justaguide eNotes educator| Certified Educator

The period of `sin^2 x - cos^2x` has to be determined.

` (sin^2 x - cos^2x) = -cos 2x`

The given expression is -cos 2x

cos x has a periodicity of `2*pi`

cos 2x has a periodicity of `pi`

The periodicity of `sin^2x - cos^2x` is `pi`

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