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The period of `sin^2 x - cos^2x` has to be determined.
` (sin^2 x - cos^2x) = -cos 2x`
The given expression is -cos 2x
cos x has a periodicity of `2*pi`
cos 2x has a periodicity of `pi`
The periodicity of `sin^2x - cos^2x` is `pi`
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