Kepler's third law of planetary motion gives us the relation between the orbital period and the distance that the body is revolving at as the square of the orbital period of the body being directly proportional to the cube of the distance from the body around which it is revolving. Or t^2 = k* r^3

Here, for Moon A, which is at a distance 1 J.D. from Jupiter, the period of completing 1 orbit is 1 day. So we have 1^2 = k * 1^3

=> k = 1

Now for Moon B, we have the distance of the orbit as 5.1 J.D.

=> t^2 = k* (5.1) ^3

=> t^2 = (5.1) ^3

=> t = (5.1) ^ (3/2)

=> t = 11.51

**Therefore the period of the Moon B is 11.51 days.**

## We’ll help your grades soar

Start your 48-hour free trial and unlock all the summaries, Q&A, and analyses you need to get better grades now.

- 30,000+ book summaries
- 20% study tools discount
- Ad-free content
- PDF downloads
- 300,000+ answers
- 5-star customer support

Already a member? Log in here.

Are you a teacher? Sign up now