# What is the perimeter of the rectangle whose length is 2 more than 3 times the width and the area is 33

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Expert Answers

hala718 | Certified Educator

Let the width of the rectangle be x, then the length is 3x +2.

Now we are given that the area if 33.

Then we know that x*(3x+2) = 33

Let us solve.

==> 3x^2 + 2x = 33

==> 3x^2 +2x - 33 = 0

==> Now we will find the roots.

==> (3x+11)(x-3) = 0

==> x 1= -11/3 (Invalid solution)

==> x2= 3

==> Then the width is 3.

==> The length = 3*3 + 2 = 11

Now we will calculate the perimeter.

==> P = 2*3 + 2*11 = 6+ 22 = 28

**Then the perimeter of the rectangle is 28 units.**