Given f(x) = 2x^2 + 3x - 20
We need to find the roots of f(x).
Then, we need to find x and f(x) values such that f(x) = 0
==> 2x^2 + 3x -20 = 0
We will use the roots formula :
==> x1= = (-3 + sqrt(9-4*2*-20) / 2*2 = (-3+sqrt9+160)/ 4 = (-3+13)/4 = 10/4 = 5/2 = 2.5
==> x2= (-3-13)/4 = -16/4 = -4
Then the roots are: (-4, 0) and ( 2.5, 0).
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