What is the number such that three times the number plus 23 equals 53?
The number is 10. Here is how to get this answer.
First, let the number be called x.
We can set up the equation
3x + 23 = 53
Once we have this, we can solve for x by doing some basic algebra. First, we must get the numbers to be on one side of the equation and the x term to be on the other side. We can do this by subtracting 23 from both sides. That gives us
3x = 30
Now we simply divide both sides by 3 and get
x = 10
Assume that the number is x
Then 3 times the number =3x
Add 23 ==> 3x+23
==> 3x+23 = 53
==> 3x= 53-23 = 30
==> x= 10
Reversing the operation we get the number.
After adding 23 we got 53.
So before adding 23 we should have the number which is
After multiplying a number we got 30.
So divide 30 by 3: 30/3 =10.
So the number is 10.
Check: 10*3+23 =53.
allow x to be the number ,
==>therefore, your equation is
set it equal and subtract 23 from both sides
3x=30, divide either side by 10
Hope this helps!