What is the multiplicative inverse of the number 3 + 2i ?

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The multiplicative inverse of 3 + 2i is the number that if multiplied by 3 + 2i gives 1.

If the multiplicative inverse is x + iy.

(x + iy)(3 + 2i) = 1

=> x +iy = 1/(3 +2i)

=> x + iy = (3 - 2i)/( 3 +...

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The multiplicative inverse of 3 + 2i is the number that if multiplied by 3 + 2i gives 1.

If the multiplicative inverse is x + iy.

(x + iy)(3 + 2i) = 1

=> x +iy = 1/(3 +2i)

=> x + iy = (3 - 2i)/( 3 + 2i)(3 - 2i)

=> x + iy = ( 3- 2i) / (9 - 4i^2)

=> x + iy = (3 - 2i)/ 13

We get x + iy = 3/13 - 2i/13

The multiplicative inverse is 3/13 - 2i/13

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