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The molarity of a solution in which a particular compound is dissolved is defined as the number of moles of the compound dissolved per liter of the solution.
Here we have 5.0 L of solution which has 200 g of CaCO3 dissolved in it. The molar mass of CaCO3 is 100.0869 g/mol. This can be taken as 100 g/mol. approximately.
200 g of CaCO3 is 200/100 = 2 moles of CaCO3.
As the 2 moles of CaCO3 is dissolved in 5 L of the solution, the resulting molarity is given by 2/5 = 0.4 mol/liter.
caco₃100g → 1mol
caco₃200g → 2mol
the amount of moles = volume(ml)*molarity*10⁻³
(get Molarity as x)
2 = 5000*x*10⁻³
2 = 5x
x = 2/5
x = 0.4M
Molarity = 0.4M
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