What is the minimum value of f(x) = 4x^2 + 4x + 1

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The minimum value of f(x) = 4x^2 + 4x + 1 is at the point x = a, which is the solution of f'(x) = 0. Also, f''(a) should be positive.

f'(x) = 8x + 4

f'(x) = 0

=> 8x + 4 = 0

=> x = -1/2

f''(x)...

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The minimum value of f(x) = 4x^2 + 4x + 1 is at the point x = a, which is the solution of f'(x) = 0. Also, f''(a) should be positive.

f'(x) = 8x + 4

f'(x) = 0

=> 8x + 4 = 0

=> x = -1/2

f''(x) = 4 which is positive for all values of x.

f(-1/2) = 4*(-1/2)^2 + 4*(-1/2) + 1 = 4*(1/4) - 2 + 1 = 0

The minimum value of f(x) = 4x^2 + 4x + 1 is 0

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