# What is the median for 50,60,70,80,90, and 100?I got 75 but the only choices in my book are a)70 b)65 c)60 d)55

*print*Print*list*Cite

Out of these choices, the only one that is possible is A. The median is 70. I think you can argue that it could also be 80, but it cannot possibly be 75. Here is why:

The median number in a set of numbers must be one of those numbers in the set. 75 is not one of the numbers that you have been given so it cannot be the median. It is easier to find the median number if you have an odd number of numbers. Because if you had 7 numbers, for example, you would pick the number where 3 are bigger and 3 are smaller.

Here, you have 6 numbers so there is no number where equal numbers are bigger and equal numbrs are smaller.

The median of a group of numbers can be determined by listing the numbers and finding the middle number of the group (i.e. 2,4,6,8,10-median=6). When there is an even number, as in this case, you find the mean of the middle two numbers (i.e. 2,4,6,8-median=5). So for your problem, you would add 70 and 80 together and then divide 150 by 2. Your answer should be 75. I am not sure why your book does not have that as an answer choice. It might be a error the publishing company made. I hope this helps.

What is the median for 50,60,70,80,90, and 100?

Since the median would be 75 since it is the middle between 70 and 80

75 should be the correct answer

50,60,70,80,90, and 100

The median is always the middle number

you are already have the numbers in order all you need to do is count to the middle left and right

50, 60, 70, 80, 90, 100

1 2 3 3 2 1

the media number is both 70 and 80 so you add them up and divide by 2

70 + 80 = 150 / 2 = 75

**75** should be the median

In statistics median of a group of values or numbers is defined as the value which is in the middle of all the values when these are arranged in increasing or decreasing order. Thus there are as many values more than the median as the values that are more than the median.

When the number of values are odd there is clearly one value which has equal number of values more and less than it. This is the median value. However, when the number of values is even there is no value which has equal number of values more and less than it. In such situations, one way to calculate medians as the average of the two central values. Th value 75 calculated by you is correct as per this method.

However in the question posed, you have to choose from the given values, and the given values contain only one of the two central values. That is the option includes only 70 as a possible answer, while 80 is not included. also among the given values 70 is closest to answer of 75 calculated by the other method. Therefor, 70 appears to be the best choice among the given values.

When arranged in an increasing order the median is the middle one.

There are six different number numbers. So you get 3rd and 4th as middle. There are two middles.

Since the trend numbers is uniform, the median lies uniformly between the middle two , i.e, 70 and 80 which is 75. But the median is non existent in the data.