# What is the maximum height reached by a stone thrown at 30 m/s at an angle 32 degrees to the horizontal. Take gravity as 10 m/s^2

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A stone is thrown with a speed of 30 m/s in a direction making an angle of 32 degrees with the horizontal. The horizontal component of the velocity of the stone is equal to 30*cos 32 and the vertical component of the velocity is 30*sin 32. As the projectile travels there is a constant acceleration of 10 m/s^2 in the vertically downwards direction. The upward velocity of the stone decreases as it rises and increases after it begins to fall once the highest point is reached.

At the highest point, the vertical component of the stone's velocity is equal to 0

Use the formula v^2 - u^2 = 2*a*s where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance traveled.

Substituting the values provided:

0 - (30*sin 32)^2 = -2*10*s

=> s = 12.63

The maximum height of the stone is 12.63 m