What mass of ammonia will exert the samepressure as 10.7 mg of hydrogen sulfide (H2S)in the same container under the same condi-tions? Answer in units of mg
We can answer this problem by employing the ideal gas law.
PV = nRT
under the same conditions we can now say that
moles ammonia= moles hydrogen sulfide
= gram H2S/ molar mass H2S
= 0.0107 grams H2S/ 34.0809 grams/mole *
= 3.139588449835538e-4 = 0.00031396 moles
moles ammonia = 0.00031396 moles
To get the mass of ammonia, we have to multiply it with the molar mass of ammonia.
mass ammonia = moles ammonia x molar mass ammonia
= 0.00031396 moles x 17.031 grams/mole
= 0.0053470330889149 = 0.00535 grams ammonia
= 5.35 mg ammonia
*we first convert mg-> g in the solution.
1000mg = 1 g
hope this helps :)