What is the magnitude and direction of the resultant force? A force of F1 of 36 N pulls at an angle of 20° above due east. Pulling in the opposite direction is a force F2 of 48 N acting at an angle of 42° below due west. I have no idea on how to set up this problem. Any help is greatly appreciated.
The force F1 component to East = 36cos20 = 33.83N
The force F1 component to North = 36sin20 = 12.31
The force F2 component to West = 48cos42 = 35.67N
The force F2 component to South = 48sin42 = 32.12N
Let take forces to East and north as positive.
Then forces to West and South are negative forces to East and North forces.
Total force to East = 33.83-35.67 = -1.84N
Total force to North = 12.31-32.12 = -19.81N
Resultant force = sqrt[(-1.84)^2+(-19.81)^2] = 19.89N
Direction of resultant force = tan^(-1) (-19.81/-1.84)
= 84.69 deg.
The resultant force is a force of 19.89N to the direction of 84.69 deg. below due west.
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