What is the limitting reactant? Ba(OH)2 * 8H20 (s) + 2NH4SCN (s) -> Ba(SCN)2 (s) + 10H2O (l) + 2NH3 (g)Each reactant is 10.0 g, which is the limitting reactant and how many moles of Ba(SCN)2 (s) is...

What is the limitting reactant?

Ba(OH)2 * 8H20 (s) + 2NH4SCN (s) -> Ba(SCN)2 (s) + 10H2O (l) + 2NH3 (g)
Each reactant is 10.0 g, which is the limitting reactant and how many moles of Ba(SCN)2 (s) is produced?

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In order to identify the limiting reactant we have to identify which between the two reactant would produce the smaller amount of products.

We can look at it this way: 

1.   Ba(OH)2 * 8H20  ------> moles Ba(SCN)2

2.   NH4SCN --------> moles Ba(SCN)2

There are two ways in which Ba(SCN)2 can be formed. The...

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