What is the limit of the sequence an=(n^2-n+7)/(2n^3+n^2) ?n tends to infinite

1 Answer | Add Yours

giorgiana1976's profile pic

giorgiana1976 | College Teacher | (Level 3) Valedictorian

Posted on

We'll force the factor n^2 to numerator and we'll get:

lim an = lim n^2*(1 - 1/n + 7/n^2)/(2n^3+n^2)

We'll force the factor n^3 to denominator and we'll get:

lim an = lim n^2*(1 - 1/n + 7/n^2)/n^3*(2 + 1/n)

We'll simplify:

lim an = lim (1 - 1/n + 7/n^2)/n*(2 + 1/n)

The limits of the sequences 1/n , 7/n^2  converge to zero, therefore we'll get:

lim an = 1/2*infinite

lim an = 1/infinite = 0

If n approaches to infinite, the given sequence (an) converges to zero.

We’ve answered 319,434 questions. We can answer yours, too.

Ask a question