We have to find the value of lim x--> inf+ [sin x / sqrt (x^2 + 1)]

sin x is a periodic function the value of which oscillates between -1 and 1 as x tends to infinity. It is not possible to determine the value of sin x for x--> inf., but we know the value is between -1 and +1.

The value of sqrt (1 + x^2) tends to infinity as x tends to inf. So the value of 1/ sqrt ( x^2 + 1) tends to zero.

This allows us to say that the value of lim x--> inf+ [sin x / sqrt (x^2 + 1)] = 0

**The required value of lim x--> inf+ [sin x / sqrt (x^2 + 1)] is 0.**