What is the limit of the fraction bn/2^n if bn=1+2+2^n, n-->infinite?

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We need to find the value of lim n--> inf [ bn/2^n]

Also, we have bn = 1 + 2 + 2^n

lim n--> inf [ bn/2^n]

=> lim n--> inf [(1 + 2 + 2^n)/2^n]

=> lim n--> inf [1/2^n + 2/2^n + 2^n/2^n]

for n--> inf , we have 2^n --> inf and (1/2^n) --> 0

lim n--> inf [1/2^n + 2/2^n + 2^n/2^n]

=> 0 + 0 + 1

The required limit = 1

[This answer is the solution to the unedited question.]

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