what is the limit of: (cos 4x)/x as the lim x goes to - infinity
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jeew-m
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We know that cosines are always between -1 and +1.
`-1<=cos(4x)<=+1`
So we can say;
`-1<=[lim_(xrarroo) cos(4x)]<=+1`
Let us say `lim_(xrarroo)cos4x = p` where `-1<=p<=+1.`
`lim_(xrarroo)(cos(4x))/x = p/oo = 0`
So the answer is `lim_(xrarroo)(cos(4x))/x = 0`
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