What is the kinetic energy of any gas molecule at 0 degrees Celsius?I want the answer related to chemistry(kinetic theory of gases).  What formulas or concepts can be used?  The answer is...

What is the kinetic energy of any gas molecule at 0 degrees Celsius?

I want the answer related to chemistry(kinetic theory of gases).  What formulas or concepts can be used?  The answer is 5.66x10^-21 Joule.

Asked on by ambika96

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ncchemist | eNotes Employee

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The kinetic theory of gases mathematically explains the behavior and energy of ideal gasses.  Essentially, the molecules of ideal gases are considered to behave as individual particles which are constantly in motion and have constant collisions with each other and their containers.  The kinetic energy of a single molecule of an ideal gas can be described by the following equation:

KE = (3/2)kT

KE is the kinetic energy, k is Boltzmann's constant (1.38 x 10^-23 J/K), and T is the temperature in Kelvin.  So the kinetic energy of any gas molecule at 0 degrees C (273 K) is:

KE = (3/2)(1.38 x 10^-23 J/K)(273 K) = 5.65 x 10^-21 J

This matches the answer that you gave.

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