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A function f(x) is even if f(x) = f(-x); and it is odd if f(-x) = -f(x).
To determine if f(x) is odd, even or neither substitute x with -x in the given function and notice what happens.
f(-x) = 4*(-x)^2 - 2*(-x)
= 4x^2 + 2x
`4x^2 + 2x != 4x^2 - 2x`
and `4x^2 + 2x != -(4x^2 - 2x)`
The function f(x) = 4x^2 - 2x is neither even nor is it odd.
You need to test the parity of function by replacing -x for x in equation of function, such that:
`f(-x) = 4*(-x)^2 - 2*(-x)`
`f(-x) = 4x^2 + 2x`
Since `f(-x)!=f(x)` and `f(-x)!=-f(x)` , hence, the function is neither even, nor odd.
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