# What is the inverse of f(x) = (3 - x)/2

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A function f(x) and its inverse `f^-1(x)` are related by `f(f^-1(x)) = x`

For `f(x) = (3 -x)/2`

`f(f^-1(x)) = x`

=> `(3 - f^-1(x))/2 = x`

=> `3 - f^-1(x) = 2x`

=> `f^-1(x) = 3 - 2x`

**The inverse function for `f(x) = (3 -x)/2` is **`f^-1(x) = 3 - 2x`

To find the inverse of the function, interchange the variables and solve for ` y` .

`x = 1/2(3-y)`

Since y is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation.

`1/2(3-y) = x`

Multiply `x` by each term inside the parentheses.

`(3-y)=2x `

Remove the parentheses around the expression `3-y` .

`3-y=2x `

Move all terms not containing `y` to the right-hand side of the equation.

`-y=2x-3 `

Divide each term in the equation by `-1` .

`y=3-2x `

Find the composition `f(f^(-1)(x))`

`f(3-2x)=x `

Since `f(f^(-1)(x)) =x , f^(-1) (x) = 3- 2x` is the inverse of `f(x) = ((3-x))/2` .

Thus, the inverse of the given equation is

`f^(-1) (x) = 3 - 2x`