What are the intercepts of y= x^2 -4x + 5 ?
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Where the curve of x^2 - 4x + 5 = 0 intercepts the y-axis, x = 0.
=> y = 0 - 0 + 5 = 5
The y-intercept is (0,5)
When the curve intercepts the x-axis, y= 0
=> x^2 - 4x + 5 = 0
Here we see that (-4)^2 < 4*a*c, the...
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The intercepts of y= x^2 -4x + 5 have to be determined.
At the point where the curve meets the x-axis, the value of the y-coordinate is 0.
The equation x^2 - 4x + 5 = 0 has to be solved to determine the x-intercepts.
But the equation x^2 - 4x + 5 = 0 does not have any real roots as (-4)^2 - 4*1*5 = -4 which is negative.
The curve does not intersect the x-axis.
At the point where it meets the y-axis, the x coordinate is 0. This gives y = 0 - 0 + 5 = 0
The y intercept of the curve is 5.
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