# what is theĀ `int (xdx)/(x+1)`

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### 1 Answer

You need to solve the integral `int (xdx)/(x+1)`

Adding and subtracting 1 to numerator yields:

`int ((x + 1 - 1)dx)/(x+1) = int ((x+1)dx)/(x+1) -int dx/(x+1)`

`int (xdx)/(x+1) =int dx - ln |x+1| + c`

`int (xdx)/(x+1) = x - ln |x+1| + c`

**Evaluating the given integral yields: `int (xdx)/(x+1) = x - ln |x+1| + c` **