The integral `int 1/(x*ln x) dx` has to be determined.
Let `ln x = y`
`dy = (1/x)*dx`
`int 1/(x*ln x) dx`
=> `int (1/y) dy`
=> `ln y`
substituting `y = ln x`
=> `ln(ln x)`
The integral `int 1/(x*ln x) dx = ln(ln x) + C`
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